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Solid Ba(NO(3))(2) is gradually dissolve...

Solid `Ba(NO_(3))_(2)` is gradually dissolved in a `10^(-4)M Na_(2)CO_(3)` solution. At what concentration of `Ba^(2+)` will a precipitate begin to form ? (`K_(sp)` for `BaCO_(3)=5.1xx10^(-9)`)

A

`4.1xx10^(-5)M`

B

`8.1xx10^(-8)M`

C

`5.1xx10^(-5)M`

D

`8.1xx10^(-7)M`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(sp)=[Ba^(2+)][CO_(3)^(2-)]`
`5.1xx10^(-9)=[Ba^(2+)]xx10^(-4)`
`[Ba^(2+)]=5.1xx10^(-5)M`.
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