The half life period of a first order chemical reaction is `6.93` minutes . The time required for the completion of `99%` of the chemical reaction will be ( log 2 = 0.301 ) :

Options

A. 230.3 minutes
B. 23.03 minutes
C. 46.06 minutes
D. 460.6 minutes

Answer

C

Explanation

(C ) `k=(0.693)/(t_(1//2))`
`= (0.693)/(6.93)=0.1 "min"^(-1)`
`t= (2.303)/(k) "log" ([A]_(0))/([A])`
`= (2.303)/(0.1) "log" (100)/(1) `
`=(2.303xx2)/(0.1) = 46 .06 min`