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The half life period of a first order ch...

The half life period of a first order chemical reaction is `6.93` minutes . The time required for the completion of `99%` of the chemical reaction will be ( log 2 = 0.301 ) :

A

230.3 minutes

B

23.03 minutes

C

46.06 minutes

D

460.6 minutes

Text Solution

Verified by Experts

The correct Answer is:
C
(C ) `k=(0.693)/(t_(1//2))`
`= (0.693)/(6.93)=0.1 "min"^(-1)`
`t= (2.303)/(k) "log" ([A]_(0))/([A])`
`= (2.303)/(0.1) "log" (100)/(1) `
`=(2.303xx2)/(0.1) = 46 .06 min`
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Knowledge Check

  • The half life period of first order chemical reaction is 6 cdot 93 minutes. The time required for the completion of 99% of chemical reaction will be (log 2 = 0 cdot 301) :

    A
    `46 cdot 06` minutes
    B
    `460 cdot 6` minutes
    C
    `230 cdot 3` minutes
    D
    `23 cdot 03` minutes

  • The half life period of first order reaction is

    A
    directly proportional to rate constant
    B
    independent of initial concentration
    C
    depends on the concentration
    D
    dependent on the rate constant

  • The half life period of a zero order reaction is equal to :

    A
    `(2k )/([A]_(0))`
    B
    `([A]_(0))/(2k)`
    C
    `(0.693)/(k)`
    D
    `(0.693)/(k[A]_(0))`

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