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According to Freundlich adsorption isoth...

According to Freundlich adsorption isotherm, the adsorption at low pressure is proporational to:

A

P

B

`1//P`

C

`P^(@)`

D

`P ^(n),` (where `n =0` to 1).

Text Solution

Verified by Experts

The correct Answer is:
A
Frendlich adsorption isotherm is
`(x)/(m) = kP ^(1//n)`
At low pressure, the graph of `(x)/(m) vs P` is almost straight line which indicates that `x/m` is directly proportional to pressure.
`(x)/(m) prop P or (x)/(m) = kP`
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Knowledge Check

  • Freundlich adsorption isotherm is:

    A
    `(x )/(m) = kp ^(n)`
    B
    `k = (x)/(m) p ^(1//n)`
    C
    `(x)/(m) = kp ^(1//n)`
    D
    `(m)/(x) = kp ^(1//n)`

  • For adsorption

    A
    `DeltaH =-ve, DeltaS= ive`
    B
    `DeltaH = +ve, DeltaS = +ve`
    C
    `DeltaH = -ve, DeltaS = +ve`
    D
    `DeltaH = +ve, DeltaS = +ve`

  • In Freundlich adsorption isotherm, the value of 1/n is :

    A
    between 0 and 1 in all cases
    B
    between 2 and 4 in all cases
    C
    1 in case of physisorption
    D
    1 in case of chemisorption

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