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If the velocity of a particle "v" as a ...

If the velocity of a particle "v" as a function of time "t" is given by the equation,v=a(1-e^(-bt) ,where a and b are constants,then the dimension of the quantity a^2*b^3 will be

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Knowledge Check

  • The velocity v of a particle at time t is given by v=at+b/(t+c) , where a, b and c are constants. The dimensions of a, b and c are respectively:-

    A
    `LT^(–2)`, L and T
    B
    `L^(2)` and `LT^(2)`
    C
    `LT^(2)`,LT and L
    D
    L,LT anf `T^(2)`

  • The velocity v of a particle at time t is given by v=at+b/(t+c) , where a, b and c are constants. The dimensions of a, b, c are respectively :-

    A
    `LT^(-2)`, L and T
    B
    `L^(2)`, T and `LT^(2)`
    C
    `LT^(2)`, LT and L
    D
    L, LT and `T^(2)`

  • The velocity v of a particle at time A is given by v = at+ (b)/(l +c) where a ,b and c are constant The dimensions of a,b and c are respectively

    A
    `[LT^(-2)],[L] and [T]`
    B
    `[L^(2)],[T] and [LT^(2)]`
    C
    `[LT^(2)],[LT] and [L]`
    D
    `[L],[LT] and [T^(2)]`

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    The position of a particle at time t, is given by the equation, x(t) = (v_(0))/(alpha)(1-e^(-alpha t)) , where v_(0) is a constant and alpha gt 0 . The dimensions of v_(0) & alpha are respectively.

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