If the velocity of a particle "v" as a function of time "t" is given by the equation,v=a(1-e^(-bt) ,where a and b are constants,then the dimension of the quantity a^2*b^3 will be

The velocity v of a particle at time t is given by v=at+b/(t+c) , where a, b and c are constants. The dimensions of a, b, c are respectively :-

The energy E of a particle at position x at time t is given by E=a/(t(b+x^(2)) Where a and b are constants. The dimensional formula of a is

The velocity v of a particle at time A is given by v = at+ (b)/(l +c) where a ,b and c are constant The dimensions of a,b and c are respectively

The velocity of the particle of mass m as a function of time t is given by v = Aomega.cos[sqrt(K/m)t] , where A is amplitude of oscillation. The dimension of A/K is

The position of a particle at time t, is given by the equation, x(t) = (v_(0))/(alpha)(1-e^(-alpha t)) , where v_(0) is a constant and alpha gt 0 . The dimensions of v_(0) & alpha are respectively.

The position of a particle at time t is given by the relation x(t)=(v_(0)/alpha)(1-e^(-alphat)) where v_(0) is a constant and alpha gt 0 . Find the dimensions of v_(0) and alpha

If the speed v of a particle of mass m as function of time t is given by v=omegaAsin[(sqrt(k)/(m))t] , where A has dimension of length.