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In solving a quadratic equation x^(2) + ...

In solving a quadratic equation `x^(2) + px + q = 0` a student made a mistake in copying the coefficient of x and obtined the root as 4, -3 but one of the actual roots is 2 what is the difference between the actual and wrong values of the coefficients of x ?

A

5

B

4

C

7

D

46

Text Solution

Verified by Experts

The correct Answer is:
A
Quadratic equation with `4,-3` as root is `x^(2)`
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Knowledge Check

  • In writing a quadratic equation of the form x^(2) + px + q = 0 ,a student makes a mistake in writing the coefficientof x and gets the roots as 8 and 12. Another student makes mistake in writing the constant term and gets the roots as 7 and 3. Find the correct quadratic equation.

    A
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    B
    `x^(2) - 20x + 21 = 0`
    C
    `x^(2) - 21x + 20 = 0`
    D
    `x^(2) - 96x + 10 = 0`

  • Two persons A and B solved a quadratic equation of the form x^(2) + bx + c = 0 . A made a mistake in noting down the coefficient of x and obtained the roots as 18 and 2, where as B obtained the roots as -9 and -3 by misreading the constrant term. The correct roots of the equation are

    A
    `-6,-3`
    B
    `-6,6`
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  • In a quadratic equation with leading coefficient 1, a student read the coefficient 16 of x wrong as 19 and obtain the roots as -15 and -4. The correct roots are

    A
    6, 10
    B
    `-6, -10`
    C
    `-7, -9`
    D
    none of these

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