1 g atom of nitrogen contains `6.023 xx 10^(23)` atoms of nitrogen.

Answer

To solve the question, "1 g atom of nitrogen contains `6.023 x 10^(23)` atoms of nitrogen," we will follow these steps:

### Step 1: Understand the concept of a mole
1. A gram atom of an element is equivalent to one mole of that element. For nitrogen (N), this means that 1 gram atom of nitrogen corresponds to 1 mole of nitrogen.

### Step 2: Use Avogadro's number
2. Avogadro's number (Na) is `6.022 x 10^(23)`, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance.

### Step 3: Determine the number of nitrogen molecules
3. Since nitrogen exists as a diatomic molecule (N2), when we refer to 1 mole of nitrogen gas (N2), we actually have 1 mole of nitrogen molecules. Therefore, the number of nitrogen molecules in 1 mole of N2 is:
\[ \text{Number of molecules} = 1 \text{ mole} \times 6.022 \times 10^{23} \text{ molecules/mole} = 6.022 \times 10^{23} \text{ molecules of N2} \]

### Step 4: Calculate the total number of nitrogen atoms
4. Since each molecule of nitrogen gas (N2) contains 2 nitrogen atoms, we can find the total number of nitrogen atoms by multiplying the number of nitrogen molecules by 2:
\[ \text{Total number of nitrogen atoms} = 2 \times (6.022 \times 10^{23}) = 1.2044 \times 10^{24} \text{ atoms of nitrogen} \]

### Conclusion
5. Therefore, the statement "1 g atom of nitrogen contains `6.023 x 10^(23)` atoms of nitrogen" is incorrect. The correct number of nitrogen atoms in 1 gram atom (or 1 mole) of nitrogen gas (N2) is `1.2044 x 10^(24)` atoms.