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One mole of carbon atom weighs 12g, the ...

One mole of carbon atom weighs 12g, the number of atoms in it is equal to, ( Mass of carbon-12 is `1.9926xx10^(-23)g`)

A

`1.2xx10^(23)`

B

`6.022xx10^(22)`

C

`12xx10^(22)`

D

`6.022xx10^(23)`

Text Solution

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The correct Answer is:
To solve the problem of finding the number of atoms in one mole of carbon, we can follow these steps: ### Step-by-Step Solution: 1. **Given Data**: - Mass of one mole of carbon atoms = 12 grams - Mass of one carbon-12 atom = \(1.9926 \times 10^{-23}\) grams 2. **Concept**: - One mole of any substance contains Avogadro's number (\(N_A\)) of particles (atoms, molecules, etc.). Avogadro's number is \(6.022 \times 10^{23}\). 3. **Calculation**: - To find the number of atoms in one mole of carbon, we use the relationship between the mass of one mole of carbon and the mass of a single carbon atom. 4. **Formula**: - Number of atoms in one mole = \(\frac{\text{Mass of one mole of carbon}}{\text{Mass of one carbon atom}}\) 5. **Substitute the values**: \[ \text{Number of atoms} = \frac{12 \text{ grams}}{1.9926 \times 10^{-23} \text{ grams/atom}} \] 6. **Perform the division**: \[ \text{Number of atoms} = \frac{12}{1.9926 \times 10^{-23}} \] 7. **Simplify the calculation**: \[ \text{Number of atoms} = 6.022 \times 10^{23} \] ### Final Answer: The number of atoms in one mole of carbon is \(6.022 \times 10^{23}\).
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Knowledge Check

  • Assertion. Both 106 g of sodium carbonate and 12 g of carbon have same number of carbon atoms. Reason. Both contain 1 g atom of carbon which contains 6.023xx10^(23) carbon atoms.

    A
    If both assertion and reason are true, and reason is the true explanation of the assertion.
    B
    If both assertion and reason are true, but reason is not the true explanation of the assetion.
    C
    If assertion is true, but reason if false
    D
    If both assertion and reason are false.
  • The number of carbon atoms in 1 g of CaCO_3 is,

    A
    `6.022 xx 10^(23)`
    B
    `6.022 xx 10^(21)`
    C
    `3.0125 xx 10^(22)`
    D
    `1.204 xx 10^(23)`
  • Number of atoms in 12 g of ""_(12)^(24)Mg is equal to

    A
    oxygen atoms in 11 g `CO_(2)`
    B
    hydrogen atoms in 4g `CH_(4)`
    C
    nitrogen atom in 46 g `N_(2)O_(4)`
    D
    sulphur atom in 79 g `Na_(2)S_(2)O_(3)`
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    Statement-1 : Both 10 g of sodium carbonate and 12 g of carbon have same number of carbon atoms Statement-2 : Both contain 1g atoms of carbon which contains 6.022 xx 10^(23) carbon atoms.