A force of 50 N act on the object of mass 20 kg calculate the acceleration of the object in x and y direction

Explanation

Given F = 50N and m= 20 kg
(i) component of force along x-direction
`F_x = F cos theta`
`= 50 xx cos 30^@ = 43.30 N`
` therefore a_x = (F_x)/(m) = (43.30)/(20) = 2.165 ms^(-2)`
(ii) Component of force along y-direction
` F_y = F sin theta = 50 xx sin 30^@ = 25N`
` therefore a_y = (F_y)/(m) = 25/20 = 1.25 ms^(-2)`