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G = 6.67xx10^(-11) N m^(2)(kg)^(-2) = ……...

`G = 6.67xx10^(-11) N m^(2)(kg)^(-2) = ………. (cm)^(3)s^(-2)g^(-1)`.

Text Solution

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`G = 6.67 xx 10^(-11) Nm^2 kg^(2)`
` = 6.67 xx 10^(-11) (kg ms^(-2) ) (m^2 kg^(-2) )`
` = 6.67 xx 10^(-11) kg^(-1) m^3 s^(-2)`
` = 6,67 xx 10^(-11) (1000g)^(-1) (100 cm)^3 (s^(-2) )`
` = 6.67 xx 10^(-11) xx 1/1000 xx 100 xx 100 g^(-1) cm^3 s^(-2)`
` = 6.67 xx 10^(-8) g^(-1) cm^3 s^(-2)`
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Convert 3 ms^(-2) "to km" h^(-2) (ii) G = 6.67 xx 10^(-11) N m^(2) kg^(-2) to cm^(3) g^(-1) s^(-2)

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Knowledge Check

  • The mass of the earth is 6xx10^(24) kg and that of the Moon is 7.4 xx10^(22) kg. The constant of gravitation G is 6.67 xx10^(-11) "Nm"^(2) "kg"^(-2) The potential energy of the system is -7.79xx10^(28) J The mean distance between the Earth and Moon is .......... metre.

    A
    `3.80 xx10^(8)`
    B
    `3.37xx10^(8)`
    C
    `7..60xx10^(8)`
    D
    `1.90xx10^(2)`

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