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The position of an object moving along x...

The position of an object moving along x axis is given by `x =a+ bt^2` here a= 8.5 m, `b = 2.5 ms^(-2)` and t is time in second. Calculate the velocity at t = 0 and t = 2 s and also calculate average velocity between t = 2 s and t = 4 s.

Text Solution

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`v = (dx)/(dt) = (d)/(dt) (a +bt^2) = 2bt = 5.0 t ms^(-1)`
At , `t = 0 , v = 0 ms^(-1)` and at `t = 2 s v = 10ms^(-1)`
average velocity ` = ( x (4) - x(2) )/(4 - 2) = (a + 16b - a - 4b)/(2) = 6b = 6 xx 2.5 = 15.0 ms^(-1)`
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