What is the heat in joules required to raise the temperature of 25 grams of `0^@C` to `100^@C`? What is the heat in Calories? (Specific heat of water `=4.18 J//g^@C` )
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Given m=25 g , `DeltaT`=(100-0)=`100^@C` or in terms of Kelvin (373.15-273.15)=100K, `C=4.18J//g^@C` Heat energy required , Q=m x C x `DeltaT` =25 x 4.18 x 100 = 10450 J
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