The maximum number of electrons in an atom with `n = 4 and l = 1` is

Explanation

To determine the maximum number of electrons in an atom with principal quantum number \( n = 4 \) and azimuthal quantum number \( l = 1 \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Quantum Numbers**:
- The principal quantum number \( n \) indicates the main energy level of the electron. Here, \( n = 4 \).
- The azimuthal quantum number \( l \) defines the shape of the orbital. For \( l = 1 \), the corresponding orbital is a p-orbital.

2. **Determine the Orbital Type**:
- Since \( l = 1 \), we are dealing with p-orbitals. The p-orbitals can hold a maximum of 6 electrons.

3. **Maximum Number of Electrons**:
- Each p-orbital can hold a maximum of 2 electrons per orbital, and there are 3 p-orbitals (i.e., \( p_x, p_y, p_z \)).
- Therefore, the total maximum number of electrons in the p-orbitals is calculated as:
\[ \text{Maximum electrons in p-orbitals} = 3 \text{ (p-orbitals)} \times 2 \text{ (electrons per orbital)} = 6 \text{ electrons} \]

4. **Conclusion**:
- Thus, the maximum number of electrons in an atom with \( n = 4 \) and \( l = 1 \) is **6 electrons**.