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The enthalpies of solution of anhydrous ...

The enthalpies of solution of anhydrous `CuSO_(4)` and hydrated `CuSO_(4). 5H_(2)O` are -66.5 and 11.7 kJ `mol^(-1)` respectively.Calculate the enthalpy of hydration of `CuSO_(4)` to `CuSO_(4).5H_(2)O`.

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To calculate the enthalpy of hydration of anhydrous CuSO₄ to form hydrated CuSO₄·5H₂O, we can use the given enthalpies of solution for both compounds. The enthalpy of hydration can be derived from the following steps: ### Step-by-Step Solution: 1. **Identify the Given Data**: - Enthalpy of solution for anhydrous CuSO₄ (ΔH₁) = -66.5 kJ/mol - Enthalpy of solution for hydrated CuSO₄·5H₂O (ΔH₂) = +11.7 kJ/mol ...
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The enthalpy of solution of anhydrous copper sulphate ( CuSO_(4)) and hydrated copper sulphate (CuSO_(4). 5 H_(2)O) are - 66.5 and +11.7 kJ mol^(-1) respectively. Calculate the enthalpy of hydration of anhydrous copper sulphate to pentahydrate.

Enthalpy of solution ofanhydrous CuSO_(4)(s) and hydrated salt, CuSO_(4).5H_(2)O(s) are - 66.5 kJ mol^(-1) and + 11.7 kJ mol^(-1) respectively. The enthalpy of hydration of CuSO_(4)(s) is "…......................"

Knowledge Check

  • The heat of solution of anhydrous CuSO_(4) and CuSO_(4).5H_(2)O are -15.89 and 2.80 Kcal mol^(-1) respectively. What will be the heat of hydration of anhydrous CuSO_(4) ?

    A
    `-18.69` Kcal
    B
    `18.69` Kcal
    C
    `-28.96` Kcal
    D
    28.96 Kcal
  • In solid CuSO_(4).5H_(2)O

    A
    Five molecules of `H_(2)O` are coordinate bonded to `Cu^(2+)`
    B
    `Cu^(2+)` ion is coordinate bonded to four water molecules
    C
    One `H_(2)O` molecule is H-bonded
    D
    It has four type of bonds : Ionic, covalent, coordinate and H-bond
  • In solid CuSO_(4).5H_(2)O

    A
    `Cu^(2+)` ion is coordinate bonded to four water molecules
    B
    One `H_(2)O` molecule is `H-` bonded
    C
    It has four types of bonds, Ionic, covalent, coordinate and H- bond
    D
    Five molecules of `H_(2)O` are coordinate bonded to `Cu^(2+)`
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    The integral enthalpies of solution of anhydrous CuSO_(4) (s) and hydrated CuSO_(4).5H_(2)O(s) are -70 kJ per mol and 10 kJ per mol respectively. Determine the magnitude of enthalpy of hydration of 0.1 mole anhydrous CuSO_(4) (s) as CuSO_(4)(s)+5H_(2)O(l)rarrCuSO_(4).5H_(2)O(s)

    The enthalpy of solution of anhydrous CuSO_(4) is -15.9 kCal and that of CuSO_(4). 5H_(2)O is 2.8 kCal. Calculate the enthalpy of hydration of CuSO_(4) .

    Heat of sol^(n) of CuSO_(4) (s) and CuSO_(4) . 5 H_(2) O is 15.9 and 19.3 kJ/mol respectively . Find the heat of hydration of CuSO_(4) (s)

    CuSo_(4) . 5 H_(2)O is a

    If the heat fo dissolution of anhydrous CuSO_(4) and CuSO_(4).5H_(2)O is -15.89 kcal and 2.80 kcal , respectively, then the heat of hydration fo CuSO_(4) to form CuSO_(4).5H_(2)O is