Calculate the C-C bond enthalpy from the following data : `2C("graphite") + 3H_(2)(g), to C_(2)H_(6)(g) Delta_(r)H^(@) = -84.67mkJ` `C("graphite"), to C(g) Delta_(r)H^(@) = 716.7kJ` `H_(2)(g), to 2H(g) Delta_(r)H^(@) = 435.9 kJ` Assume 416 kJ as the C-H bond enthalpy.
Text Solution
AI Generated Solution
To calculate the C-C bond enthalpy from the provided data, we will follow these steps:
### Step 1: Write the target reaction
We need to find the bond enthalpy for the C-C bond in ethane (C2H6). The reaction we want to consider is:
\[ \text{C}_2\text{H}_6(g) \rightarrow 2\text{C}(g) + 6\text{H}(g) \]
### Step 2: Identify the given reactions
1. \( 2\text{C}(\text{graphite}) + 3\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(g) \quad \Delta_rH^(@) = -84.67 \text{ kJ} \) (Equation 1)
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Calculate the C-C bond energy from the following data : (i) 2 C ( graphite ) +3H_(2)(g) rarr C_(2)H_(6)(g), DeltaH =- 84.67 kJ (ii) C ( graphite ) rarr C(g), Delta H = 716 .7 kJ (iii) H_(2)(g) rarr 2H(g), Delta H = 435.9 kJ Assume the C-H bond energy as 416 kJ
Calculate the standard N- H bond enthalpy from the following data : N_(2(g)) + 2H_(2(g)) to 2NH_(3(g)) Delta H^(@) = - 83 kJ Delta H^(@) (N= N) = 946 kJ mol^(-1) , Delta H^(@) (H-H) 436 kJ mol^(-1)
Knowledge Check
The enthalpy change for the reaction 2C("graphite")+3H_(2)(g)rarrC_(2)H_(6)(g) is called
A
Enthalpy of formation
B
Enthalpy of combustion
C
Enthalpy of hydrogenation
D
Enthalpy of vaporisation
Calculate the bond energy of C-H bond from the following data : (a) C (s) + 2 H_(2) (g) to CH_(4) (g) , Delta H = -74.8 KJ (b) H_(2) (g) to 2 H (g) , Delta H = 435.4 KJ (c) C(s) to C(g) , Delta H = 718.4 KJ
A
316.0 KJ/mol
B
416 KJ/mol
C
516 KJ/mol
D
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MODERN PUBLICATION-THERMODYNAMICS-Unit Practice Test