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The more positive the value of E^(0), th...

The more positive the value of `E^(0)`, the greater is the tendency of the species to get reduced. Using the standard electrode potential of redox couples given below find out which of the following is the strongest oxidising agent.
`E^(0)` values:
`Fe^(3+)//Fe^(2+) = +0.77, I_(2)(s)//I^(-) = +0.54`,
`Cu^(2+)//Cu = +0.34, Ag^(+)//A = 0.80V`

A

`Fe^(3+)`

B

`I_2(s)`

C

`Cu^(2+)`

D

`Ag^+`

Text Solution

Verified by Experts

The correct Answer is:
D

`Ag^(+)|Ag` is most positive and therefore , `Ag^+` is the strongest oxidising agent .
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The more positive the value of E^(@) the greater is the tendency of the species to get reduced using the standard electrode potential of redox couples given below find out which of the following is the strongest oxidising agent E^(@) "values" : (F^(3+))/(Fe^(2+))=+0.77, I_(2)(s)//I^(-)=+0.54,(Cu^(2+))/(Cu^(2+))=+0.34, (Ag^(+))/(Ag(s))=+0.80,Cu^(2+)//Cu(s)=+0.34 (I_(s))/(I)^(-)=+0.54

Knowledge Check

  • The more positive the value of E^(θ) , the greater is the trendency of the species to get reduced. Using the standard electrode potential of redox coples given below find out which of the following is the strongest oxidising agent. E^(θ) values: Fe^(3+)//Fe^(2+) = +0.77 I_(2)(s)//I^(-) = +0.54 , Cu^(2+)//Cu = +0.34, Ag^(+)//A = 0.80V

    A
    `Fe^(3+)`
    B
    `I_(2)(s)`
    C
    `Cu^(2+)`
    D
    `Ag^(+)`
  • The more positive the value of E^(-) , the tendency of the species to get reduced. Using the electrode potential of redox couples given below. Which of the following is the strongest oxidising agent. E^(-) values, Fe^(3+)//Fe^(2+) = + 0.77 I_(2)(s)//I^(-) = +0.54 , Cu^(2+)//Cu = +0.34, Ag^(+)//Ag = 0.80 V

    A
    `Fe^(3+)`
    B
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    C
    `Cu^(2+)`
    D
    `Ag^(+)`
  • The more positive the value of E^(-) , the tendency of the species to get reduced. Using the electrode potential of redox couples given below. Which of the following is the strongest oxidising agent. E^(-) values, Fe^(3+)//Fe^(2+) = + 0.77 I_(2)(s)//I^(-) = +0.54 , Cu^(2+)//Cu = +0.34, Ag^(+)//Ag = 0.80 V

    A
    `Fe^(3+)`
    B
    `I_(2)(S)`
    C
    `Cu^(2+)`
    D
    `Ag^(+)`
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