The ozonolysis of `(CH_(3))_(2)C=C(CH_(3))_(2)` followed by treatment with zinc and water will give

Options

A. acetone
B. acetaldehyde and acetone
C. acetic acid
D. formaldehyde

Explanation

To solve the problem of the ozonolysis of `(CH₃)₂C=C(CH₃)₂` followed by treatment with zinc and water, we can break down the steps as follows:

### Step 1: Identify the Structure of the Alkene
The given alkene is `(CH₃)₂C=C(CH₃)₂`, which can be represented as:
```
CH₃
|
CH₃-C=C-CH₃
|
CH₃
```
This structure indicates that we have a symmetrical alkene with two methyl groups on each side of the double bond.

### Step 2: Perform Ozonolysis
Ozonolysis involves the reaction of the alkene with ozone (O₃), which cleaves the double bond and forms ozonides. The double bond in the alkene breaks, and we get two carbonyl groups (C=O) on either side of the original double bond.

### Step 3: Identify the Products of Ozonolysis
When we perform ozonolysis on our symmetrical alkene, the double bond breaks and forms two identical carbonyl compounds. The structure after ozonolysis will be:
```
O
||
CH₃-C-CH₃
|
O
```
This results in two molecules of acetone (CH₃COCH₃).

### Step 4: Treatment with Zinc and Water
The next step involves treating the ozonide with zinc and water. This step is known as reductive ozonolysis. In this reaction, the ozonide is reduced to yield aldehydes or ketones. Since we already have acetone from the ozonolysis, this step will not change the product.

### Final Product
Thus, the final product after ozonolysis followed by treatment with zinc and water is:
- **Acetone (CH₃COCH₃)**

### Conclusion
The ozonolysis of `(CH₃)₂C=C(CH₃)₂` followed by treatment with zinc and water will give **acetone**.

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