Total number of nitrogen atoms presentin reduced product obtained by reducing nitrobenzene with `LiAlH_(4)` followed by aqueous work up is

Explanation

To solve the question regarding the total number of nitrogen atoms present in the reduced product obtained by reducing nitrobenzene with LiAlH4 followed by aqueous workup, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant**: The starting compound is nitrobenzene, which has the structure C6H5NO2. It contains one nitrogen atom in the nitro group (-NO2).

2. **Understand the Reducing Agent**: Lithium aluminum hydride (LiAlH4) is a strong reducing agent. It can reduce nitro groups (-NO2) to amines. Specifically, it reduces nitrobenzene to an intermediate product.

3. **Reduction Process**: When nitrobenzene is treated with LiAlH4, the nitro group (-NO2) is reduced to an amine group (-NH2). The reaction can be summarized as:
\[ \text{C}_6\text{H}_5\text{NO}_2 \xrightarrow{\text{LiAlH}_4} \text{C}_6\text{H}_5\text{NH}_2 \]
This means that nitrobenzene is converted to aniline (C6H5NH2), which contains one nitrogen atom from the original nitro group.

4. **Aqueous Workup**: The subsequent aqueous workup does not change the number of nitrogen atoms in the product. It simply helps in isolating the amine product.

5. **Final Product**: The final product after the reduction of nitrobenzene with LiAlH4 followed by aqueous workup is aniline (C6H5NH2), which contains one nitrogen atom from the nitro group.

6. **Counting Nitrogen Atoms**: In the final product (aniline), there is 1 nitrogen atom.

### Conclusion:
The total number of nitrogen atoms present in the reduced product (aniline) is **1**.