The temperature of a gas contained in a closed vessel of constant volume increases by `1^(@)C` when the pressure of the gas is increased by 1%. The initial temperature of the gas is:

Options

A. 100 K
B. `273^(@)C`
C. `100^(@)C`
D. 200 K

Answer

A

Explanation

According to Gay Lussac.s law `p prop T`
`therefore (dp)/(p) xx100 =(dT)/(T)xx100`
`1=(1)/(T) xx100`
`rArr T=100 K`
So, correct choice is (a).