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The molarity of 98% H2SO4 (d = 1.8 g/mL...

The molarity of 98% `H_2SO_4` (d = 1.8 g/mL) by weight is

A

6 M

B

18 M

C

10 M

D

4 M

Text Solution

Verified by Experts

The correct Answer is:
B
98% `H_2SO_4` means 98g `H_2SO_4` is in 100 g solution
volume of 100 g solution ` = (100)/(1.8) = 55.55 ml `
Molarity ` = ("number of moles of " H_2SO_4)/("volume of solution ") xx 1000`
` = (98)/(98 xx 55.55) xx 1000 = 18 M `
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