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If 224 ml of a triatomic gas has a mass ...

If 224 ml of a triatomic gas has a mass of 1 g at N.T.P., then the mass of one atom is :

A

`9.3 xx 10^(-23) g `

B

`2.08 xx 10^(-23) g`

C

`5.53 xx 10^(-23) g `

D

`9.62 xx 10^(-23) g `

Text Solution

Verified by Experts

The correct Answer is:
C
224 ml of gas weigh = 1g
22400 ml of gas weigh
` = (1)/(224) xx 22400 = 100 g `
` therefore ` molecular mass of gas = 100
mass of one molecule ` = (100)/(6.02 xx 10^23)`
mass of atom ` = (100)/(6.02 xx 10^23) xx 1/3 ` (triatomic gas)
= `5.53 xx 10^(-23) g `
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Knowledge Check

  • If 22.4 ml of a triatomic gas has a mass of 0.048 g at 273K and 1 atm pressure, then the mass of one atom is:

    A
    `7.9 xx 10^(-23) g `
    B
    `2.6 xx 10^(-23) g `
    C
    `2.4 xx 10^(-22) g `
    D
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  • One litre of an unknown gas weighs 1.25 g at NTP. The possible formula of the gas is :

    A
    `N_2`
    B
    CO
    C
    `SO_2`
    D
    `O_2`

  • Specific heat at constant pressure C_(p) for a diatomic gas at N.T.P. in the units of cal mole k is:

    A
    `4 cdot 95`
    B
    `6 cdot 93`
    C
    `8 cdot 93`
    D
    1

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