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In which of the following arrangements, ...

In which of the following arrangements, the sequence is not strictly according to the property written against it?

A

`CO_(2)ltSiO_(2)ltSnO_(2)ltPbO_(2)` : Increasing oxidising power

B

`HF lt HCl lt HBr lt HI`: Increasing acid strength

C

`NH_(3) lt PH_(3)ltAsH_(3)ltSbH_(3):` Increasing basic strength

D

`B lt C lt O lt N`: Increasing first ionisation enthalpy.

Text Solution

Verified by Experts

The correct Answer is:
C

On moving down the group, the size of central atom increases. Due to this, availability of lone pair of electrons decreases. Hence the basic character decreases.
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Knowledge Check

  • In which of the following arrangement, the sequence is not strictly according to the property written against it ?

    A
    `NH_3 lt PH_3 lt AsH_3 lt SbH_3` : increasing basic strength
    B
    B lt C lt O lt N : increasing first ionisation enthalpy
    C
    `CO_2 lt SiO_2 lt SnO_2 lt PbO_2` : increasing oxidation power
    D
    HF lt HCl lt HBr lt HI : increasing acid strength
  • In which of the following arrangements the order is NOT according to the property indicated against it?

    A
    `Al^(3+)ltMg^(2+)gtNa^(2+)gtF^(-)` - increasing ionic size
    B
    `BltCltNltO` - increasing first ionization enthalpy
    C
    `IltBrltFltCl` - increasing electron gain enthalpy (with negative sign)
    D
    `LiltNaltKltRb` - increasing metallic radius.
  • Which of the following arrangements does not represent the correct order of the property stated against it?

    A
    `Sc lt Ti lt Cr lt Mn:` number of oxidation states
    B
    `V^(2+) lt Cr^(2+) lt Mn^(2+) lt Fe^(2+)`: paramagnetic behaviour
    C
    `Ni^(2+) lt Co^(2+) lt Fe^(2+) lt Mn^(2+):` Ionic size
    D
    `Co^(3+) lt Fe^(3+) lt Cr^(3+) lt Sc^(3+)`: stability in aqueous solution.
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