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A tank is 7 m long and 4 m wide . At wh...

A tank is 7 m long and 4 m wide . At what speed should water run through a pipe 5 cm broad and 4 cm deep, so that in 6h and 18 min , water level in the tank rises by 4.5 m ?

A

12 km/h

B

10km/h

C

14km/h

D

18km/h

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break it down into manageable parts: ### Step 1: Calculate the Volume of Water Required to Raise the Tank Level The dimensions of the tank are given as: - Length = 7 m - Width = 4 m - Height increase = 4.5 m To find the volume of water required to raise the water level by 4.5 m, we use the formula for the volume of a rectangular prism: \[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} \] Substituting the values: \[ \text{Volume} = 7 \, \text{m} \times 4 \, \text{m} \times 4.5 \, \text{m} = 126 \, \text{m}^3 \] ### Step 2: Convert the Volume to Cubic Centimeters Since the dimensions of the pipe are given in centimeters, we need to convert the volume from cubic meters to cubic centimeters. 1 cubic meter = 1,000,000 cubic centimeters. So, \[ 126 \, \text{m}^3 = 126 \times 1,000,000 \, \text{cm}^3 = 126,000,000 \, \text{cm}^3 \] ### Step 3: Calculate the Time in Minutes The total time given is 6 hours and 18 minutes. We need to convert this time into minutes. \[ \text{Total time} = 6 \times 60 + 18 = 378 \, \text{minutes} \] ### Step 4: Calculate the Volume of Water Flowing Through the Pipe The cross-sectional area of the pipe is given as: - Width = 5 cm - Depth = 4 cm The area \( A \) of the pipe is: \[ A = \text{Width} \times \text{Depth} = 5 \, \text{cm} \times 4 \, \text{cm} = 20 \, \text{cm}^2 \] If water flows through the pipe at a rate of \( x \) cm/min, the volume of water flowing through the pipe in 1 minute is: \[ \text{Volume per minute} = A \times x = 20 \, \text{cm}^2 \times x \, \text{cm/min} = 20x \, \text{cm}^3/\text{min} \] ### Step 5: Calculate the Total Volume of Water Flowing in 378 Minutes The total volume of water that flows through the pipe in 378 minutes is: \[ \text{Total Volume} = 20x \times 378 = 7560x \, \text{cm}^3 \] ### Step 6: Set Up the Equation According to the problem, the total volume of water flowing through the pipe must equal the volume required to raise the tank level: \[ 7560x = 126,000,000 \] ### Step 7: Solve for \( x \) Now, we can solve for \( x \): \[ x = \frac{126,000,000}{7560} = 16666.67 \, \text{cm/min} \] ### Step 8: Convert \( x \) to m/s To find the speed in meters per second, we convert from centimeters per minute to meters per second: \[ x = \frac{16666.67 \, \text{cm/min}}{100} \times \frac{1}{60} = 2.77778 \, \text{m/s} \] ### Final Answer The speed at which water should run through the pipe is approximately **2.78 m/s**. ---
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