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`alpha` ,`beta`, `gamma` are the roots of the equation `x^(3)-3x^(2)+6x+1=0`. Then the centroid of the triangle whose vertices are `(alpha beta,1/(alpha beta))`, `(beta gamma, 1/(beta gamma))` , `(gamma alpha,1/(gamma alpha))` is

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If alpha, beta gamma are the real roots of the equation x^(3)-3px^(2)+3qx-1=0 , then find the centroid of the triangle whose vertices are (alpha, (1)/(alpha)), (beta, (1)/(beta)) and (gamma, (1)/(gamma)) .

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Knowledge Check

  • If alpha,beta, gamma are the real roots of the equation x^(3)-3ax^(2)+3bx-1=0 , then the centroid of the triangle whose vertices are the points (alpha, 1/(alpha)), (beta, 1/(beta)) and (gamma,1/(gamma)) is the point

    A
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    B
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    C
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    D
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    A
    `x^(3)+3x+11=0`
    B
    `x^(3)-3x-11=0`
    C
    `x^(3)+3x-11=0`
    D
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  • If alpha, beta and gamma are the roots of the equation x^(3)+x+2=0 , then the equation whose roots are (alpha- beta)(alpha-gamma), (beta-gamma)(beta-gamma) and (gamma-alpha)(gamma-alpha) is

    A
    `x^(3)-6x^(2)+216=0`
    B
    `x^(3)-3x^(2)+112=0`
    C
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    D
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