Home
Class 10
CHEMISTRY
The equilibrium constant for the reactio...

The equilibrium constant for the reaction `N_(2_(g)) + O_(2_(g)) hArr 2NO_(g)` and `NO_(g)hArr +(1)/(2)N_(2(g)) +(1)/(2)O_(2(g))` are k and `K^(1)` , respectively, the relation between k and `k^(1)` is

A

`k=(k^(1))^(2)`

B

`k=((1)/(k^(1)))^(2)`

C

`k^(2)=k^(1)`

D

`k^(1)=((1)/(k))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL KINETICS AND EQUILIBRIUM

    PEARSON IIT JEE FOUNDATION|Exercise Level 2|22 Videos
  • CHEMICAL KINETICS AND EQUILIBRIUM

    PEARSON IIT JEE FOUNDATION|Exercise Level 3|10 Videos
  • CHEMICAL KINETICS AND EQUILIBRIUM

    PEARSON IIT JEE FOUNDATION|Exercise Essay type questions|1 Videos
  • ATOMIC STRUCTURE

    PEARSON IIT JEE FOUNDATION|Exercise LEVEL-3|8 Videos
  • CHEMICAL BONDING

    PEARSON IIT JEE FOUNDATION|Exercise Level 3|10 Videos

Similar Questions

Explore conceptually related problems

The equilibrium constant for N_(2)(g) + O_(2)(g) hArr 2NO(g) is K, then calculate equilibrium constant for 1//2N_(2)(g) + 1//2O_(2)(g) hArr NO(g) .

At a given temperature, the equilibrium constant for the reactions NO(g)+1//2O_(2)(g)hArr NO_(2)(g) and 2NO_(2)(g)hArr 2NO(g)+O_(2)(g) are K_(1) and K_(2) respectivel. If K_(1) is 4xx10^(-3) then K_(2) will be

Knowledge Check

  • The equilibrium constant for the reaction, N_(2(g))+3H_(2(g)) to 2NH_(3(g)) and 2N_(2(g)) +6H_(2(g))to 4NH_(3(g)) are K_1 and K_2 , respectively. The relationship between K_1 and K_2 is

    A
    `K_2=K_1^(-1)`
    B
    `K_2=K_(1)^(-2)`
    C
    `K_1=K_2^2`
    D
    `K_1=sqrtK_2`
  • The equilibrium constant of the reactions SO_(2)(g)+1/2 O_(2)(g)hArrSO_(3)(g) and 2SO_(2)(g)+O_(2)hArr2SO_(3)(g) are K_(1) and K_(2) respectively. The relationship between K_(1) and K_(2) is

    A
    `K_(1)=K_(2)`
    B
    `K_(2)^(2)=K_(1)`
    C
    `K_(1)^(2)=K_(2)`
    D
    `K_(2)=sqrt(K_(1))`
  • The equilibrium constant for N_(2)(g)+O_(2)(g)hArr2NO "is" K_(1) and that for NO(g)hArr(1)/(2)N_(2)(g)+(1)/(2)O_(2)(g) is K_(2). K_(1) "and" K_(2) will be related as

    A
    `K_(1)=((1)/(K_(2)))^(2)`
    B
    `K_(1)=K_(2)^(2)`
    C
    `K_(2)=((1)/(K_(1)))^(2)`
    D
    `K_(2)=K_(1)^(2)`
  • Similar Questions

    Explore conceptually related problems

    K_(1) and K_(2) are equilibrium constants for reaction (i) and (ii) N_(2)(g)+O_(2)(g) hArr 2NO(g) …(i) NO(g) hArr 1//2 N_(2)(g)+1//2O_(2)(g) …(ii) then,

    If the equilibrium constant for N_(2)(g)+O_(2)(g) hArr 2NO(g) is K, the equilibrium constant for (1)/(2)N_(2)(g)+(1)/(2)O_(2)(g) hArr NO(g) will be :

    K_(p)//K_(c) for the reaction CO(g)+1/2 O_(2)(g) hArr CO_(2)(g) is

    In the equilibrium constant for N_(2)(g) + O_(2)(g)hArr2NO(g) is K, the equilibrium constant for (1)/(2) N_(2)(g) + (1)/(2)O_(2)(g)hArrNO(g) will be:

    K_(p)//K_(c) " for the reaction " CO(g) + 1/2 O_(2) (g) hArr CO_(2) (g) is