Home
Class 12
PHYSICS
Figure shows a disc of radius R=20cm wit...

Figure shows a disc of radius R=20cm with a portion of it removed symmetrically. The removed part is a disc of radius R/2. The removed part is now placed in contact with the larger disc. Centres of all the three discs lie on x-axis. Disc has uniform mass distribution. With respect to origin at centre of larger disc find x-coordinate of center of mass of system (in cm).

Answer

Step by step text solution for Figure shows a disc of radius R=20cm with a portion of it removed symmetrically. The removed part is a disc of radius R/2. The removed part is now placed in contact with the larger disc. Centres of all the three discs lie on x-axis. Disc has uniform mass distribution. With respect to origin at centre of larger disc find x-coordinate of center of mass of system (in cm). by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The given figure shows a disc of radius R=20 cm with a portion of it removed symmetrically. The removed part is a disc, of radius R / 2 . The removed part is now placed in contact with the larger disc as shown in the figure. The disc has uniform mass distribution. With respect to origin O at centre of larger disc, find x -coordinate (in cm ) of the centre of mass of system. '(##CEN_KSR_PHY_JEE_C08_E01_011_Q07##)'

Determine the coordinates of centre of mass of a half disc. Of mass M and radius R, assuming uniform mass disribution.

Knowledge Check

  • A disc of radius r is cut from a larger disc of radius 4r in such a way that the edge of the hole touches the edge of the disc. The centre of mass of the residual disc will be a distance from centre of larger disc :-

    A
    `(r)/(5)`
    B
    `(r)/(4)`
    C
    `(r)/(2)`
    D
    `(r)/(3)`

  • A circular disc of radius 20cm is cut from one edge of a larger circular disc of radius 50cm . The shift of centre of mass is

    A
    `5.7 cm`
    B
    `-5.7 cm`
    C
    `3.2 cm`
    D
    `-3.2 cm`

  • The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is

    A
    `MR^(2)`
    B
    `1/2MR^(2)`
    C
    `3/2MR^(2)`
    D
    `7/2MR^(2)`

    • Similar Questions

    Explore conceptually related problems

    The diagram shows a part of disc of radius R carrying uniformly distributed charge of density sigma . Electric potential at the centre O of parent disc is

    A circular disc of radius R is removed from a bigger of the discs coincide. The centre of mass of the new disc is ar from the centre of the bigger disc. The value of alpha is

    A circular disc of radius R is removed from a bigger circular disc of radius 2R, such that the circumference of the disc coincides. The centre of mass of the new disc is αR from the centre of bigger disc. The value of alpha is

    A circular disc of radius R is removed from a bigger circular dise of radius such that the circumferences of the discs coincide. The centre of mass of the new disc is alphaR from the centre of the bigger disc. The value of a is:

    In the figure one fourth part of a uniform disc of radius R is shown. The distance of the centre of mass of this object from centre 'O' is :

    Home
    Profile