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Two vertices of an equilateral triangle ...

Two vertices of an equilateral triangle are (0,0) and (`3, sqrt(3)`) then the third vertex can be

A

(`sqrt(3), 3`)

B

`(-3, sqrt(3))`

C

`(3, -sqrt(3))`

D

`(-sqrt(3), 3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • Two vertices of an equilateral triangle are (-1,0) and (1,0) then its circumcircle is

    A
    `x^2 + (y - 1/(sqrt3))^2 = 4/3`
    B
    `x^2 + (y + 1/(sqrt3))^2 = 1/3`
    C
    `x^2 + (y - 1/(sqrt3))^2 + 4/9 = 0`
    D
    `x^2 + y^2 = 4/3`

  • The vertices of a triangle are (3, 0), (3,3) and (0, 3). Then the coordinates of the circumcentre are

    A
    (0, 0)
    B
    (1, 1)
    C
    `((5)/(2), (5)/(2))`
    D
    `((3)/(2), (3)/(2))`

  • The third vertex of an equilateral triangle whose vertices are (2, 4), (2, 6)

    A
    (`2+sqrt3`, 5)
    B
    (`2sqrt3`, 5)
    C
    (`sqrt2`, 5)
    D
    (`sqrt3`, 5)

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