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A tin contains a mixture of Dew and Spri...

A tin contains a mixture of Dew and Sprite in the ratio of `7:3` and another tin contain the Dew and Sprite in the ratio of 5:4. In what proportion should the solution of two tins be mixed to achieve a perfect proportion of 2:1 (in which Dew is 2 times that of sprite).

A

`10:3`

B

`4:1`

C

`3:10`

D

`3:1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of mixing two tins containing Dew and Sprite in specific ratios to achieve a desired ratio, we can follow these steps: ### Step 1: Identify the Ratios - Tin 1 contains Dew and Sprite in the ratio of 7:3. - Tin 2 contains Dew and Sprite in the ratio of 5:4. - We want to mix them to achieve a final ratio of Dew to Sprite of 2:1. ### Step 2: Calculate the Fraction of Dew in Each Tin For Tin 1: - Total parts = 7 (Dew) + 3 (Sprite) = 10 - Fraction of Dew in Tin 1 = \( \frac{7}{10} \) For Tin 2: - Total parts = 5 (Dew) + 4 (Sprite) = 9 - Fraction of Dew in Tin 2 = \( \frac{5}{9} \) ### Step 3: Calculate the Fraction of Dew in the Desired Mixture For the desired mixture (2:1 ratio): - Total parts = 2 (Dew) + 1 (Sprite) = 3 - Fraction of Dew in the mixture = \( \frac{2}{3} \) ### Step 4: Set Up the Allegation Method Using the allegation method, we can find the ratio in which the two tins should be mixed. - Dew fraction in Tin 1 = \( \frac{7}{10} \) - Dew fraction in Tin 2 = \( \frac{5}{9} \) - Dew fraction in the mixture = \( \frac{2}{3} \) ### Step 5: Apply the Allegation Formula Using the formula: - Difference between the Dew fraction in the mixture and Tin 1: \[ \frac{2}{3} - \frac{7}{10} \] To calculate this, we need a common denominator (which is 30): \[ \frac{2 \times 10}{30} - \frac{7 \times 3}{30} = \frac{20}{30} - \frac{21}{30} = -\frac{1}{30} \] - Difference between the Dew fraction in Tin 2 and the mixture: \[ \frac{5}{9} - \frac{2}{3} \] Again, using a common denominator (which is 9): \[ \frac{5}{9} - \frac{6}{9} = -\frac{1}{9} \] ### Step 6: Find the Ratio Now we have: - The difference for Tin 1: \( \frac{1}{30} \) - The difference for Tin 2: \( \frac{1}{9} \) The ratio of Tin 1 to Tin 2 is given by: \[ \text{Ratio} = \frac{\frac{1}{9}}{\frac{1}{30}} = \frac{30}{9} = \frac{10}{3} \] ### Final Answer Thus, the two tins should be mixed in the ratio of **10:3**.
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Knowledge Check

  • Two liquids A and B are in the ratio 5:1 in container 1 and 1:3 in container 2. In what ratio should the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1 : 1?

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    B
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