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In how many ways can the following prize...

In how many ways can the following prizes be given away to a class of 30 students, first and second in Mathematics, first and second in Physics, first in Chemistry and first in English?

A

`(30!)/(4!)`

B

`(30 )^4 xx(29)^2`

C

`(30)^3-1`

D

`(30)^4 xx(29 )^4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many ways the prizes can be given away to a class of 30 students, we can break it down step by step. ### Step-by-Step Solution: 1. **Identify the Prizes and Students:** - We have a total of 30 students. - The prizes to be awarded are: - First and second in Mathematics - First and second in Physics - First in Chemistry - First in English 2. **Calculate the Ways to Award Mathematics Prizes:** - For the first prize in Mathematics, any of the 30 students can win. So, there are 30 choices. - After the first prize is awarded, only 29 students are left for the second prize. So, there are 29 choices for the second prize. - Therefore, the total ways to award Mathematics prizes = \(30 \times 29\). 3. **Calculate the Ways to Award Physics Prizes:** - Similarly, for the first prize in Physics, any of the 30 students can win, giving us 30 choices. - After awarding the first prize, 29 students remain for the second prize. So, there are 29 choices for the second prize. - Therefore, the total ways to award Physics prizes = \(30 \times 29\). 4. **Calculate the Ways to Award Chemistry Prize:** - For the Chemistry prize, only the first prize is awarded. Any of the 30 students can win this prize, so there are 30 choices. - Therefore, the total ways to award Chemistry prizes = \(30\). 5. **Calculate the Ways to Award English Prize:** - For the English prize, only the first prize is awarded. Any of the 30 students can win this prize, so there are 30 choices. - Therefore, the total ways to award English prizes = \(30\). 6. **Combine All the Choices:** - To find the total number of ways to award all the prizes, we multiply the number of choices for each subject: \[ \text{Total Ways} = (30 \times 29) \times (30 \times 29) \times 30 \times 30 \] 7. **Calculate the Final Result:** - This simplifies to: \[ \text{Total Ways} = (30 \times 29)^2 \times 30^2 \] - Now, calculating: \[ = 870 \times 870 \times 900 = 756300 \] ### Final Answer: The total number of ways to award the prizes is **756300**. ---
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Knowledge Check

  • The number of ways in which the following prizes be given to a class of 20 boys, first and second mathematics, first and second physics , first chemistry and first english is

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    `20^3 times 19^3`
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    D
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