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An aqueous solution of 2% non-volatile s...

An aqueous solution of 2% non-volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute ?

Text Solution

Verified by Experts

Vapour pressure of pure water at the boiling point = 1 atm = 1.013 bar
Vapour pressure of solution=1.004 bar
Mass of solute = 2 g
Mass of solution = 100 g
Mass of solvent = 100 - 2 = 98 g
Applying Raoult.s law,
`(p^@ -p_S)/(p^@) = X_2 ~= (w_2 xx m_1) /(m_2 xx W_1) `
`(1.013 -1.004 )/(1.013 ) =(2xx 10 )/(M_2 xx 98 )`
`or M_2 =(2xx 18xx 1.013 )/(0.009xx 98 )`
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