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Write the cell reaction for the electroc...

Write the cell reaction for the electrochemical cell represented as
`Zn(s)|Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s)`

Text Solution

Verified by Experts

The overall cell reaction is `Zn(s)+Cu^(2+)(aq)toZn^(2+)(aq)+Cu(s)`
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Write Nernst equation for the following cell reaction : Zn(s) | Zn^(2+)(aq)|| Cu^(2+)(aq) | Cu(s)

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Knowledge Check

  • What is the DeltaG^(@) value for the electrochemical cell below? Cu(s) | Cu^(2+)(aq) || NO_(3)^(-)(aq) | NO(s) | Pt(s)

    A
    `-753` kJ
    B
    `-359` kJ
    C
    `-179` kJ
    D
    `-59.8` kJ

  • Select the correct cell reaction of the cell Ag(s)|Ag^+(aq)"||"cu^(2+)(aq)"|"cu(s) :

    A
    `2Ag(s)+cu(s)tocu^(+2)(aq)+2Ag^+(aq)`
    B
    `cu(s)+2Ag^+(aq)tocu^(2+)(aq)+2Ag(s)`
    C
    `2Ag(s)+cu^(2+)(aq)tocu(s)(aq)+2Ag^+(aq)`
    D
    `cu^(2+)(aq)+2Ag^+(aq)to2Ag(s)+cu(s)`

  • E^(@) for the electrochemical cell Zn(s)|Zn^(2+) 1 M (Aq.)||Cu^(2+) 1 M (aq.)|Cu(s) is 1.10 V at 25^(@)C . The equilibrium constant for the cell reaction, Zn(s) +Cu^(2+) (aq.) hArr Zn^(2+) (aq.)+Cu(s) Will be :

    A
    `10^(-37)`
    B
    `10^(37)`
    C
    `10^(-39)`
    D
    `10^(39)`

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    Write the cell reaction from the cell notation Zn(s)|Zn^(2+)(aq)||Pb^(2+)(aq)|Pb

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    Calculate the maximum work that can be obtained from the daniell call given below, Zn(s)|Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s) . Given that E_(Zn^(2+)//Zn)^(@)=-0.76V and E_(Cu^(2+)//Cu)^(@)=+0.34V .

    E^@ for the alectrochemical cell Zn(S)|Zn^(2+) 1M(aq)||Cu^(2+)1M(aq)|Cu(s) is 1.10 at 25^@ . The equilibrium constant for the cell reaction, Zn(S)+Cu^(2+) (aq.) Leftrightarrow Zn^(2+) (aq.) +Cu(s) will be:

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