34.05 mL of phosphorus vapour weights 0.0625 g at `546^(@)C` and 1 bar pressure. What is the molar mass of phosphorus?

Explanation

To find the molar mass of phosphorus vapor, we can use the ideal gas equation, which is given by:

\[ PV = nRT \]

Where:
- \( P \) = pressure (in bar)
- \( V \) = volume (in liters)
- \( n \) = number of moles
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