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34.05 mL of phosphorus vapour weights 0....

34.05 mL of phosphorus vapour weights 0.0625 g at `546^(@)C` and 1 bar pressure. What is the molar mass of phosphorus?

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To find the molar mass of phosphorus vapor, we can use the ideal gas equation, which is given by: \[ PV = nRT \] Where: - \( P \) = pressure (in bar) - \( V \) = volume (in liters) - \( n \) = number of moles ...
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