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Find the centre of mass of the shaded po...

Find the centre of mass of the shaded portion of a disc.

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`X_(cm)=(m_(2)(0)-m_(1)((3R)/(4)))/(m_(2)-m_(1))=(-3R)/(4((m_(2))/(m_(1))-1))`
where `(m_(2))/(m_(1))=((pi R^(2))rho)/(pi((R )/(4))^(2)rho)=16`
`rArr X_(cm)=-(3R)/(4(16-1))=-(R )/(20)`
Note : Negative mass is taken because the mass is removed.
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