Home
Class 12
PHYSICS
Find the centre of mass of the shaded po...

Find the centre of mass of the shaded portion of a disc.

Text Solution

Verified by Experts

`X_(cm)=(m_(2)(0)-m_(1)((3R)/(4)))/(m_(2)-m_(1))=(-3R)/(4((m_(2))/(m_(1))-1))`
where `(m_(2))/(m_(1))=((pi R^(2))rho)/(pi((R )/(4))^(2)rho)=16`
`rArr X_(cm)=-(3R)/(4(16-1))=-(R )/(20)`
Note : Negative mass is taken because the mass is removed.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • COLLISION

    FIITJEE|Exercise SOLVED PROBLEMS (OBJECTIVE)|18 Videos

  • COLLISION

    FIITJEE|Exercise SOLVED PROBLEMS (OBJECTIVE) ASSERTION REASONING TYPE|1 Videos

  • COLLISION

    FIITJEE|Exercise (NUMERICAL BASED QUESTIONS)|4 Videos

  • AC CIRCUITS

    FIITJEE|Exercise ASSERTION REASONING TYPE|1 Videos

  • CURRENT ELECTRICITY

    FIITJEE|Exercise Comprehension -4|3 Videos

Similar Questions

Explore conceptually related problems

Find the centre of mass x_(CM) of the shaded portion of the disc of radius R = 24 cm .

From a uniform circular dis of radius R , a circular dis of radius R//6 and having centre at a distance R//2 from the centre of the disc is removed. Determine the centre of mass of remaining portion of the disc.

Knowledge Check

  • The centre of mass of the shaded portion of the disc is: ( The mass is uniformly distributed in the shaded portion).

    A
    `R/20` to the left of A
    B
    `R/12` to the left of A
    C
    `R/20` to the right of A
    D
    `R/12` to the right of A

  • Find the perimeter and area of the shaded portion of the adjoining diagram:

    A
    `90.8 cm, 414 cm^(2)`
    B
    `181.6 cm, 423.7 cm^(2)`
    C
    `90.8 cm, 827.4 cm^(2)`
    D
    `181.6 cm, 827.4 cm^(2)`

    • Similar Questions

    Explore conceptually related problems

    Find the area of the shaded portion.

    From a square sheet of uniform density , a portion a removed shown shaded in fig. Find the centre of msas of the remaining portion is the side of the square is alpha

    (i) Write the fraction of the shaded portion:

    A circular disc of radius (R)/(4) is cut from a uniform circular disc of radius R. The centre of cut portion is at a distance of (R)/(2) from the centre of the disc from which it is removed. Calculate the centre of mass of remaining portion of the disc.

    Find the centre of mass of a thin, uniform disc of radius R from which a small concentric disc of radius r is cut.

    Find the centre of mass of the disc shown in figure. . A square is removed from the disc as shown

    Home
    Profile