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A disc of radius R is placed on a square...

A disc of radius R is placed on a square plate of edge 4R made up of the same sheet with their planes parallel such that any two adjacent sides ofsquare touch the disc. Find the distance of the centre of mass of the system from the centre of square plate?

Text Solution

Verified by Experts

Let us consider that `sigma` = mass / area of the sheet
Mass of disc `= m_(1) = pi R^(2) sigma` & mass of square plate `= 16 R^(2)sigma`
By geometry OP. = OP = R
`C_(1)C_(2)=2sqrt(2)R-sqrt(2)R=sqrt(2)R`
`therefore X_(cm)=(sqrt(2)Rxx pi R^(2)sigma + 0 xx 16 R^(2)sigma)/((16+pi)R^(2)sigma)=(sqrt(2)pi R)/(16+pi)` along
`C_(1)C_(2)` from `C_(1)`
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Knowledge Check

  • From a circular disc of radius R , a triangular portion is cut (sec figure). The distance of the centre of mass of the remainder from the centre of the disc is -

    A
    `(4R)/(3(pi-2))`
    B
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    D
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  • Figure shows a square plate of uniform thickness and side length sqrt 2 m . One fourth of the plate is removed as indicated. The distance of centre of mass of the remaining portion from the centre of the original square plate is

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    `1//3m`
    B
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    C
    `1//6 m`
    D
    `1//8m`
  • In the figure one fourth part of a uniform disc of radius R is shown. The distance of the centre of mass of this object from centre 'O' is :

    A
    `(4R)/(3pi)`
    B
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    C
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