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A sphere of mass m is moving with a velo...

A sphere of mass m is moving with a velocity `(4 hat(i)-hat(j))` m/s hits a surface and rebounds with a velocity `(hat(i)+3hat(j))` m/s. The coefficient of restitution between the sphere and the surface is k/16. find the value of k.

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To solve the problem, we need to find the value of \( k \) given the coefficient of restitution \( e = \frac{k}{16} \). The coefficient of restitution is defined as the ratio of the relative velocity of separation to the relative velocity of approach along the line of impact. ### Step-by-Step Solution: 1. **Identify Initial and Final Velocities:** - The initial velocity \( \vec{u} \) of the sphere is given as: \[ \vec{u} = 4 \hat{i} - \hat{j} \, \text{m/s} \] - The final velocity \( \vec{v} \) after rebounding is: \[ \vec{v} = \hat{i} + 3 \hat{j} \, \text{m/s} \] 2. **Calculate the Change in Momentum:** - The impulse experienced by the sphere can be calculated as: \[ \text{Impulse} = m(\vec{v} - \vec{u}) = m\left((\hat{i} + 3\hat{j}) - (4\hat{i} - \hat{j})\right) \] - Simplifying this gives: \[ \text{Impulse} = m\left(-3\hat{i} + 4\hat{j}\right) \] 3. **Determine the Direction of Impulse:** - The unit vector along the direction of impulse is given by: \[ \hat{n} = \frac{\text{Impulse}}{|\text{Impulse}|} \] - First, we find the magnitude of the impulse: \[ |\text{Impulse}| = m \sqrt{(-3)^2 + 4^2} = m \sqrt{9 + 16} = m \sqrt{25} = 5m \] - Thus, the unit vector is: \[ \hat{n} = \frac{-3\hat{i} + 4\hat{j}}{5m} \] 4. **Calculate the Components of Velocities Along the Direction of Impulse:** - The component of \( \vec{u} \) along \( \hat{n} \): \[ u_1 = \vec{u} \cdot \hat{n} = (4\hat{i} - \hat{j}) \cdot \left(\frac{-3\hat{i} + 4\hat{j}}{5}\right) \] - Calculating this gives: \[ u_1 = \frac{1}{5} (4 \cdot -3 + (-1) \cdot 4) = \frac{1}{5} (-12 - 4) = \frac{-16}{5} \] - The component of \( \vec{v} \) along \( \hat{n} \): \[ v_1 = \vec{v} \cdot \hat{n} = (\hat{i} + 3\hat{j}) \cdot \left(\frac{-3\hat{i} + 4\hat{j}}{5}\right) \] - Calculating this gives: \[ v_1 = \frac{1}{5} (-3 + 12) = \frac{9}{5} \] 5. **Apply the Coefficient of Restitution Formula:** - The coefficient of restitution \( e \) is defined as: \[ e = \frac{\text{Velocity of Separation}}{\text{Velocity of Approach}} = \frac{v_1 - 0}{0 - u_1} = \frac{v_1}{-u_1} \] - Substituting the values: \[ e = \frac{\frac{9}{5}}{-\left(-\frac{16}{5}\right)} = \frac{9}{16} \] 6. **Relate \( e \) to \( k \):** - From the problem, we know: \[ e = \frac{k}{16} \] - Setting the two expressions for \( e \) equal gives: \[ \frac{k}{16} = \frac{9}{16} \] - Therefore, solving for \( k \): \[ k = 9 \] ### Final Answer: The value of \( k \) is \( 9 \).
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A sphere of mass m is moving with a velocity 4hat"i"+3hat"j"-5hat"k" when it hits a smooth wall and rebounds with velocity 2hat"i"+2hat"j"+3hat"k" . Find the impulse it receives. Find also the coefficient of restitution between the sphere and the wall.

A particle of mass 'm' moving with a velocity of (4hat(i)-hat(j))m//s strikes a fixed wall and finally moves with a velocity of (3hat(i)+2hat(j))m//s . Find (a) the impulse received by the particle. (b) the coefficient of restitution between them in the collision.

Knowledge Check

  • A small sphere of mass 1 kg is moving with a velocity (6hat(i)+hat(j))ms^(-1) . It hits a fixed smooth wall and rebound with velocity (4hat(i)+hat(j))ms^(-1) . The coefficient of restitution between the sphere and the wall is

    A
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    B
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    C
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    D
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  • A smooth sphere is moving on a horizontal surface with velocity vector 3hat(i) + hat(j) immediately before it hits a vertical wall. The wall is parallel to the vector hat(j) and the coefficient of restitution between the wall and sphere is (1)/(3) . The velocity vector of the sphere after it hits the wall is :-

    A
    `hat(i) + hat(j)`
    B
    `3hat(i) - (1)/(3) hat(j)`
    C
    `-hat(i) + hat(j)`
    D
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    A
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    B
    `(5 hat(i)-hat(j))m//s`
    C
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    D
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