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The coefficient of linear expansion of a...

The coefficient of linear expansion of a rod is `alpha` and its length is L. The increase in temperature required to increase its legnth by 1% is

A

`1/(alpha)`

B

`1/(10 alpha)`

C

`1/(50 alpha)`

D

`1/(100 alpha)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the increase in temperature required to increase the length of a rod by 1% given its coefficient of linear expansion, denoted as \( \alpha \), and its original length \( L \). ### Step-by-Step Solution: 1. **Understand the Concept of Linear Expansion**: The change in length (\( \Delta L \)) of a rod due to a change in temperature (\( \Delta T \)) is given by the formula: \[ \Delta L = \alpha L \Delta T \] where: - \( \alpha \) is the coefficient of linear expansion, - \( L \) is the original length of the rod, - \( \Delta T \) is the change in temperature. 2. **Identify the Change in Length**: We are told that the length of the rod increases by 1%. This means: \[ \Delta L = 0.01 L \] 3. **Set Up the Equation**: Substitute \( \Delta L \) into the linear expansion formula: \[ 0.01 L = \alpha L \Delta T \] 4. **Simplify the Equation**: We can cancel \( L \) from both sides (assuming \( L \neq 0 \)): \[ 0.01 = \alpha \Delta T \] 5. **Solve for \( \Delta T \)**: Rearranging the equation to find \( \Delta T \): \[ \Delta T = \frac{0.01}{\alpha} \] 6. **Final Result**: The increase in temperature required to increase the length of the rod by 1% is: \[ \Delta T = \frac{1}{100 \alpha} \]
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Knowledge Check

  • The diameter of a fly wheel is R . Its coefficient of linear expansion is alpha . If its temperature is increased by deltaT the percentage increase in its moment of inertia is

    A
    `200xxalphaxxDeltaT`
    B
    `100xxalphaxxDeltaT`
    C
    `50xxalphaxxDeltaT`
    D
    `150xxalphaxxDeltaT`
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    A
    `(alphaAcl)/d`
    B
    `(dcl)/(Aalpha)`
    C
    `(cl alphad)/A`
    D
    `(dAcl)/(alpha)`
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    A
    `(L)/(2)`
    B
    L
    C
    Between L and 2L
    D
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