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A catalyst increases the rate of chemica...

A catalyst increases the rate of chemical reaction by providing an alternative reaction pathway which lowers the activation energy than the reaction pathway in its absence. A catalyst is not consumed and therefore does not appear in the chemical equation for the reaction. A homogenous catalyst is in the same phase as the ractants whilst a heterogeneous catalyst is in a different phase.
The complex `[Co(NH_(3))_(3)F]^(2+)+H_(2)Oto[Co(NH_(3))_(5)(H_(2)O+F^(-)]^(3+)`
and Rate `=k["complex"]^(a).[H^(+)]^(b)`
The reaction is acid catalysed , i.e. `[H^(+)]` does not change during the reaction . Thus, rate `=k'["complex"]` where, `k'=[H^(+)]^(b)`

From the above data, value of a is :

A

`1`

B

`2`

C

`0`

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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A catalyst increases the rate of a chemical reaction by

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Knowledge Check

  • A catalyst increases the rate of chemical reaction by providing an alternative reaction pathway which lowers the activation energy than the reaction pathway in its absence. A catalyst is not consumed and therefore does not appear in the chemical equation for the reaction. A homogenous catalyst is in the same phase as the ractants whilst a heterogeneous catalyst is in a different phase. The complex [Co(NH_(3))_(3)F]^(2+)+H_(2)Oto[Co(NH_(3))_(5)(H_(2)O+F^(-)]^(3+) and Rate =k["complex"]^(a).[H^(+)]^(b) The reaction is acid catalysed , i.e. [H^(+)] does not change during the reaction . Thus, rate =k'["complex"] where, k'=[H^(+)]^(b) Overall order of reaction is

    A
    `1`
    B
    `2`
    C
    `0`
    D
    `(1)/(2)`
  • A catalyst increases the rate of a chemical reaction by

    A
    increasing the activation energy
    B
    decreasing the activation energy
    C
    reacting with reactant
    D
    reacting with products
  • A catalyst increases the rate of a chemical reaction by

    A
    increasing the activation energy
    B
    decreasing the activation energy
    C
    increasing the average KE of the molecules
    D
    increasing the number of active molecules
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