(i)Which one out of `Fe^(2+)`and `Fe^(3+)` ions is more paramagnetic and why (ii)Which of the following ions are expected to be coloured and why`Fe(_2+), Mn^(2+), Cr^(3+), Cu(+) Sc^(3+), Ti^(4+)`
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`Fe^(3+)` is more paramagnetic than `(Fe^(2+)` as `Fe^(3+)`has five unpaired electrons while `Fe^(2+)` possesses four unpaired electrons The ions of transition elements which possess unpaired electrons show a characteristic colour, due to d-d transition`(n-1)d^(0)or(N-1)^(10)` configuration does not involve d-d transition and hence, is colourless. `Fe^(2+), Mn^(2+)` and `Cr^(3+)` are coloured while `Cu^(+), Sc^(3+)` and `Ti^(4+)` are colourless
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