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A: At very high pressures, compressibili...

A: At very high pressures, compressibility factor is greater than 1.
R: At very high pressure, 'b' can be neglected in van der Waals gas equation

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)

C

If Assertion is true statement but Reason is false, then mark (3)

D

If both Assertion and Reason are false statements, then mark (4)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we will analyze both the assertion (A) and the reason (R) provided. ### Step 1: Understanding the Assertion (A) The assertion states that "At very high pressures, compressibility factor is greater than 1." - The compressibility factor (Z) is defined as: \[ Z = \frac{PV}{RT} \] where P is pressure, V is volume, R is the ideal gas constant, and T is temperature. - At high pressures, real gases deviate from ideal behavior. The compressibility factor (Z) becomes greater than 1, indicating that the gas is less compressible than an ideal gas. ### Step 2: Understanding the Reason (R) The reason states that "At very high pressure, 'b' can be neglected in van der Waals gas equation." - The van der Waals equation is given by: \[ \left(P + \frac{a n^2}{V^2}\right)(V - nb) = nRT \] - Here, 'a' accounts for the attraction between particles, and 'b' accounts for the volume occupied by the gas particles. - At very high pressures, the volume (V) becomes very small, and the term 'b' (which represents the volume occupied by gas molecules) cannot be neglected. In fact, it becomes significant. ### Step 3: Analyzing the Truth of A and R - From the analysis: - The assertion (A) is **true** because at very high pressures, Z is indeed greater than 1. - The reason (R) is **false** because at very high pressures, 'b' cannot be neglected. ### Conclusion - Therefore, the assertion is true, but the reason is false. ### Final Answer - Assertion (A) is true, and Reason (R) is false.
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Knowledge Check

  • At high pressure, the compressibility factor Z is equal to

    A
    unity
    B
    `1-(Pb)/(RT)`
    C
    `1+(Pb)/(RT)`
    D
    Zero
  • At very high pressure, the compressibility factor of one mole of a gas is given by :

    A
    `1+(Pb)/(RT)`
    B
    `(Pb)/(RT)`
    C
    `1-(Pb)/(RT)`
    D
    `1-(b)/((VRT))`
  • At very high pressures, the compressibility factor of one mole of a gas is given by:

    A
    `1+(pb)/(RT)`
    B
    `(Pb)/(RT)`
    C
    `1-(pb)/(RT)`
    D
    `1-b/((VRT))`
  • Similar Questions

    Explore conceptually related problems

    At high pressure, the compressibility factor for one mole of van der Waals gas will be

    A : At high pressure , the compressibility factor Z is (1 + (pb)/(RT)) . R : At high pressure van der Wall's equation is modified as p(V - b) = RT .

    Assertion. At high pressure, the compressibility factor Z is (1+(Pb)/(RT)) . Reason. At high pressure, van der Waals equation is modified as P(V-b)=RT.

    At a high pressure, the compressibility factor (Z) of a real gas is usually greater than one. This can be explained from van der Waals equation by neglecting the value of:

    At high pressure, the compressibility factor for one mole of van der waals gas will be