0.20 g of organic compound gave 0.5544 g of `BaSO_(4)`. The percentage of S is

Options

A. 38
B. 19
C. 18
D. 83

Explanation

To find the percentage of sulfur (S) in the organic compound, follow these steps:

### Step 1: Determine the Molar Mass of Barium Sulfate (BaSO₄)
The molar mass of BaSO₄ is given as 233 g/mol. This includes:
- Barium (Ba): 137 g/mol
- Sulfur (S): 32 g/mol
- Oxygen (O): 16 g/mol × 4 = 64 g/mol
Thus, the total is:
\[ \text{Molar mass of BaSO₄} = 137 + 32 + 64 = 233 \, \text{g/mol} \]

### Step 2: Calculate the Moles of BaSO₄ Produced
Using the mass of BaSO₄ obtained:
\[ \text{Mass of BaSO₄} = 0.5544 \, \text{g} \]
To find the moles of BaSO₄:
\[ \text{Moles of BaSO₄} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{0.5544 \, \text{g}}{233 \, \text{g/mol}} \]

Calculating this gives:
\[ \text{Moles of BaSO₄} = 0.00238 \, \text{mol} \]

### Step 3: Determine the Moles of Sulfur in BaSO₄
From the formula of BaSO₄, we know that 1 mole of BaSO₄ contains 1 mole of sulfur. Therefore:
\[ \text{Moles of S} = \text{Moles of BaSO₄} = 0.00238 \, \text{mol} \]

### Step 4: Calculate the Mass of Sulfur
Using the atomic mass of sulfur (32 g/mol):
\[ \text{Mass of S} = \text{Moles of S} \times \text{Atomic Mass of S} = 0.00238 \, \text{mol} \times 32 \, \text{g/mol} \]

Calculating this gives:
\[ \text{Mass of S} = 0.07616 \, \text{g} \]

### Step 5: Calculate the Percentage of Sulfur in the Organic Compound
Using the formula for percentage:
\[ \text{Percentage of S} = \left( \frac{\text{Mass of S}}{\text{Mass of Organic Compound}} \right) \times 100 \]

Substituting the values:
\[ \text{Percentage of S} = \left( \frac{0.07616 \, \text{g}}{0.20 \, \text{g}} \right) \times 100 \]

Calculating this gives:
\[ \text{Percentage of S} = 38.08\% \]

### Final Answer
The percentage of sulfur in the organic compound is approximately **38%**.