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In how many ways can 12 things be equall...

In how many ways can 12 things be equally divided :
(i) between 2 persons (ii) into 2 heaps ?

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The correct Answer is:
To solve the problem of dividing 12 things equally, we will tackle both parts of the question step by step. ### Part (i): Dividing 12 things between 2 persons 1. **Understanding the Problem**: We need to divide 12 distinct items between 2 persons. Each person will receive 6 items. 2. **Choosing Items for One Person**: We can choose 6 items out of 12 for the first person. The number of ways to choose 6 items from 12 is given by the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] Here, \( n = 12 \) and \( r = 6 \): \[ \binom{12}{6} = \frac{12!}{6!6!} \] 3. **Calculating the Value**: \[ \binom{12}{6} = \frac{12!}{6!6!} \] This can be simplified as: \[ \binom{12}{6} = \frac{12 \times 11 \times 10 \times 9 \times 8 \times 7}{6 \times 5 \times 4 \times 3 \times 2 \times 1} = 924 \] 4. **Considering the Two Persons**: Since the two persons are different, we do not need to divide by 2. Thus, the total number of ways to divide the items is: \[ \text{Total ways} = 924 \] ### Part (ii): Dividing 12 things into 2 heaps 1. **Understanding the Problem**: Here, we need to divide 12 distinct items into 2 heaps. Each heap can have any number of items, including zero. 2. **Choosing Items for One Heap**: We can choose any number of items for one heap. If we choose \( k \) items for the first heap, the remaining \( 12 - k \) items will automatically go to the second heap. 3. **Calculating the Total Combinations**: The number of ways to choose \( k \) items from 12 is given by: \[ \sum_{k=0}^{12} \binom{12}{k} \] However, since the heaps are indistinguishable (i.e., Heap A and Heap B are the same as Heap B and Heap A), we need to divide by 2 to avoid double counting: \[ \text{Total ways} = \frac{1}{2} \left( \sum_{k=0}^{12} \binom{12}{k} \right) \] 4. **Using the Binomial Theorem**: The sum of the binomial coefficients is given by: \[ \sum_{k=0}^{n} \binom{n}{k} = 2^n \] Therefore, for \( n = 12 \): \[ \sum_{k=0}^{12} \binom{12}{k} = 2^{12} = 4096 \] 5. **Final Calculation**: Now we divide by 2: \[ \text{Total ways} = \frac{4096}{2} = 2048 \] ### Final Answers: (i) The number of ways to divide 12 things between 2 persons is **924**. (ii) The number of ways to divide 12 things into 2 heaps is **2048**.
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Knowledge Check

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    A
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    B
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    C
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    D
    none of these
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