Obtain the binding energy (in MeV) of a nitrogen nucleus `(""_7^14 N)`, given m `(""_7^14N) = 14.00307 u` .

Explanation

`BE = [{Zm_P + (A -Z)m_N}-M]c^2`
Binding energy of `""_7^14N = [{7 xx 1.007825 + 7 xx 1.008665} - 14.00307] 931( :. 1u = 931 (MeV)/(c^2))`
`= 104.61 MeV`.