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A semiconductor has the electron concent...

A semiconductor has the electron concentration `0.45 xx 10^(12) m^(-3)` and hole concentration `5 xx 10^(29) m^(-3)` . Find its conductivity . Given electron mobility = `0.135 m^(2) V^(-1) s^(-1)` and hole mobility = `0.048 m^(2) V^(-1) s^(-1) , e = 1.6 xx 10^(-19) C`

Text Solution

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`3.845 Omega^(-1) m^(-1)`
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A semiconductor is known to have an electron concentration of 8 xx 10^(13) cm^(-3) and a hole concentration of 5 xx 10^(12) cm^(-3) . a . Is the semiconductor n- type of p-type ? b. What is the resistitivity of the simple , if the electron mobility is 23,000 cm^(2) V^(-1) s^(-1) and hole mobility is 100 cm^(2) V^(-1) s^(-1) ? Take charge on electron , e = 1.6 xx 10^(-19) C .

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Knowledge Check

  • A pure semiconductor has equal electron and hole concentration of 10^(16) m^(-3) . Doping by indium increases n_(h) to 5 xx 10^(22) m^(-3) . Then the value of n_(e) in the doped semiconductor is

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