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The measurement of the electron position...

The measurement of the electron position is associated with an uncertainty in momentum, which is equal to `1 xx 10^-18 g cm s^-1`. The uncertainty in electron velocity is (mass of an electron is `9 xx 10^-28 g`)

A

`1xx10^5 "cm s"^(-1)`

B

`1xx10^11 "cm s"^(-1)`

C

`1.1xx10^9 "cm s"^(-1)`

D

`1xx10^6 "cm s"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta p=1xx10^(-18)`
`Deltav=(1xx10^(-18))/(9xx10^(-28)) rArr Deltav=1/9xx10^10`
`=0.11xx10^10 = 1.1xx10^9` cm/sec
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Knowledge Check

  • The uncertainty in the momentum of an electron is 1.2x10^-5 kg ms^-1 .The uncertainty in its position will be

    A
    `1.50x10^-26m
    B
    `1.05x 10^-26m`
    C
    `5.27x10^-30 m`
    D
    `5.25x10^-28 m`

  • The mass of the electrons 9.8 xx 10^(-28) gram and uncertainty in the velocity equal to 2 xx 10^(-3) cm//sec . The uncertainty in the position of an electron is (h = 6.62 xx 10^(-27) ergsec)

    A
    `2.9 xx 10^(+2)cm`
    B
    `2.9 xx 10^(-2)cm`
    C
    `2.9 xx 10^(-12)cm^(-1)`
    D
    `2.9 xx 10^(+12)cm^(-1)`

  • The uncertainty in momentum of an electron is 1 xx 10^-5 kg m//s . The uncertainty in its position will be (h = 6.62 xx 10^-34 kg m^2//s) .

    A
    `1.05 xx 10^-28 m`
    B
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    C
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    D
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