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In Millikan's oil drop experiment, the d...

In Millikan's oil drop experiment, the distance between the metal plates, A and B to which an electric potential is applied such that A is positive and B is negative is 5 mm. An oil drop is found to be suspended at a distance of 2 mm from B. Predict the change in the position of the oil drop when there is a sudden drop or rise in potential. Justify.

Text Solution

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(i) charge acquired by oil drop
(ii) different forces acting on the charged oil drop when it is a distance of 2mm from B.
(iii) relation between position of oil drop and different forces
(iv) effect of a particular force on the position of oil drop .ltbr gt (v) change in position ofoil drop with change in potential.
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Knowledge Check

  • In the Millikan's experiment, the distance between two horizontal plates is 2.5 cm and the potential difference applied is 250 V .The electric field between the plates will be

    A
    900 V/m
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    C
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    D
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  • In Millikan's oil drop experiment an oil drop of radius r and change Q is held in equilibrium between the plates of a charged parallel plate capacitor when the potential change is V . To keep a drop radius 2r and with a change 2Q is equilibriu between the plates the potential difference V' required is:

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    `V`
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    C
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  • In Millikan's oil drop experiment an oil drop carrying a charge Q is held stationary by a potential difference 2400 V between the plates. To keep a drop of half the radius stationary the potential difference had to be made 600 V . What is the charge on the second drop ?

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