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Phosphorous can form PCl(5) molecule in ...

Phosphorous can form `PCl_(5)` molecule in the excited state of phosphorous atom. But the formation of `PH_(5)` is not possible in the same state. How do you account for this?

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To understand why phosphorus can form \( PCl_5 \) but cannot form \( PH_5 \), we need to analyze the bonding characteristics and orbital interactions involved in both cases. ### Step-by-Step Solution: 1. **Electron Configuration of Phosphorus**: - Phosphorus (P) has the atomic number 15. Its electron configuration is \( 1s^2 2s^2 2p^6 3s^2 3p^3 \). - In the ground state, phosphorus has 5 valence electrons (2 in the 3s orbital and 3 in the 3p orbitals). ...
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Phosphorous can form PCl_(5) molecule in the excited state of phosphorous atom. But the formation of PH_(5) is not possible in the same state. Account for this.

What do you understand by ground state and excited state of an atom?

Knowledge Check

  • A : PH_(5) is not possible . [R] : -5 oxidation state of phosphorus is not possible .

    A
    If both Assertion & Reason are true and the reason is the correct explanation of the assertion , then mark (1)
    B
    If both Assertion & Reason are true but the reason is not the correct explanation of the assertion , then mark (2)
    C
    If Assertion is true statement but Reason is false , then mark (3)
    D
    If both Assertion and Reason are false statements , then mark (4)
  • In case of nitrogen, NCl_(3) is possible but not NCl_(5) while in case of phosphorous, PCl_(5) are possible. It is due to

    A
    availability of vacant d-orbitals in P but not in N
    B
    lower electronegativity of P than N
    C
    lower tendency of H-bond formation in P than N
    D
    occurrence of P in solid while N in gaseous state at room temperature.
  • In case of nitrogen, NCl_(3) is possible but not NCl_(5) while in case of phosphorous, PCl_(5) as well as PCl_(5) are possible. It is due to

    A
    Availability of vacant d-orbital in P but not in N
    B
    Lower electronegativity of P than N
    C
    Lower tendency of H bond formation in P than N
    D
    Occurrence of P in solid while N in gaseous state at room temperature
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