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A charge of 5 C is moved between two poi...

A charge of 5 C is moved between two point is an electric field and 20 J of work was done to do so. Calculate the potential difference between the two points.

Text Solution

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Given, work done , w = 20 J and charge q = 5 C
`:.` The pontential differene between the points,
`DeltaV = (w)/(q) = (20 J)/(5 C) = 4` volt.
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Knowledge Check

  • The potential difference between two points also called

    A
    voltage
    B
    work
    C
    electric power
    D
    rating

  • Potential difference between two points is equal to

    A
    `("Work done")/("charge")`
    B
    Charge `xx` work done
    C
    `("Charge")/("work done")`
    D
    `("(charge)"^(2))/("work done")`

  • On moving a charge of 20 coulomb by 2cm, 2J of work is done, then the potential difference between the points is

    A
    (a) 0.1V
    B
    (b) 8V
    C
    (c) 2V
    D
    (d) 0.5V

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    Calculate the work done to move 500 xx 10^(18) , electrons between two points in an electric field where the potential difference between the two point is 1 millivolt (e = 1.6 xx 10^(-19)C)

    A 5C charge experience a force of 2000 N when moved between two points separated by a distance of 2 cm in a uniform electric field. The potential difference between the two points is

    On moving a charge of 20 coulomb by 2 cm , 2J of work is done , the potential difference between the points is .

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