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The ration of minimum wavelengths of Lym...

The ration of minimum wavelengths of Lyman and Balmer series will be

A

1.25

B

0.25

C

5

D

10

Text Solution

Verified by Experts

The correct Answer is:
B

The wavelength of Lyman series is given by
`(1)/(lambda)=R[(1)/(l^(2))-(1)/(n^(2))]`
Where n=2,3,4,…………
For minimum wavelength,`n=oo`
`therefore (1)/((lambda_(min))_(Lyman))=(R)/(1)` .........(i)
The wavelength of Balmer series is given by
`(1)/(lambda)=R[(1)/(2^(2))-(1)/(n^(2))]`
Where n=3,4,5.........
For minimum wavelength ,`n=oo`
`therefore(1)/((lambda_(min))_(Balmer))=(R)/(4)`............(ii)
Divide (ii)by (i),we get
`((lambda_(min))_(Lyman))/(lambda_(min))_(Balmer)=(1)/(4)=0.25`
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Knowledge Check

  • The ratio of minimum wavelengths of Lyman and Balmer series will be

    A
    1.25
    B
    0.25
    C
    5
    D
    10
  • The energy of electron in the nth orbit of hydrogen atom is expressed as E_m=(-13.6)/(n^(2)) eV. The shortest and longest wavelength of Lyman series will be

    A
    910Å, 1213Å
    B
    5463Å, 7858Å
    C
    1315Å, 1530Å
    D
    None of these
  • The ratio of the largest to shortest wavelength in Balmer series of hydrogen spectra is :

    A
    `(25)/(9)`
    B
    `(17)/6`
    C
    `9/5`
    D
    `5/4`
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