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A body falls freely for 10 sec Its avera...

A body falls freely for 10 sec Its average velocity during this journey ( take = `10ms^(-2)`)

A

`100ms^(-1)`

B

`10ms^(-2)`

C

`50ms^(-1)`

D

`5ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
c
Average velocity ,
`V_(va)= ("Net displacement")/("Time taken") = (s_(2)-S_(1))/(t_(2)-t_(1)`
Here, `t_(1)=0S,S_(1)=0m,t_(2)=10s, g=10ms^(-2)`
`S_(2)=ut_(2)+(1)/(2)gt=0xx10+(1)/(2)xx10xx10^(2)=500m`
`therefore V_(av)= (500-0)/(10-0)=50ms^(-1)`
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Knowledge Check

  • A gun weighing 100 kg is used to fire an iron ball weigh ing 1 kg horizontally from a cliff of height 500 m above the ground. The ball falls 400 m away from the bottom of the cliff. What is the recoil velocity of the gun? (Take g =10 ms^(-2))

    A
    `0.8 ms^(-1)`
    B
    `0.4 ms^( -1)`
    C
    `1.2 ms^(-1)`
    D
    `0.2 ms^(-1)`

  • A car completes the first half of its journey with a velocity upsilon_(1) and the rest half with a velocity upsilon_(2) . Then the average velocity of the car for the whole journey is :

    A
    `(upsilon_(1) + upsilon_(2))/(2)`
    B
    `sqrt(upsilon_(1)upsilon_(2))`
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