A body falls freely for 10 sec Its average velocity during this journey ( take = `10ms^(-2)`)

Options

A. `100ms^(-1)`
B. `10ms^(-2)`
C. `50ms^(-1)`
D. `5ms^(-1)`

Answer

c

Explanation

Average velocity ,
`V_(va)= ("Net displacement")/("Time taken") = (s_(2)-S_(1))/(t_(2)-t_(1)`
Here, `t_(1)=0S,S_(1)=0m,t_(2)=10s, g=10ms^(-2)`
`S_(2)=ut_(2)+(1)/(2)gt=0xx10+(1)/(2)xx10xx10^(2)=500m`
`therefore V_(av)= (500-0)/(10-0)=50ms^(-1)`