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The hydrogen electrode is dipped in a so...

The hydrogen electrode is dipped in a solution of pH 3 at `25^@C`. The potential of the cell would be `(2.303 RT//F = 0.059V)` :

A

`0.177V`

B

`0.087V`

C

`0.059V`

D

`-0.177V`

Text Solution

Verified by Experts

The correct Answer is:
d
`pH=3[H^(+)]=10^(-3)`
`E_(red)^(o)+0.059log[ion]`
`E=0+0.059log[10^(-3]`
`E=+0.059(-3)=-0.177V`
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