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The expected spin magnetic moment of Fe...

The expected spin magnetic moment of `Fe^(3+)` is :

A

4

B

7

C

5

D

6

Text Solution

Verified by Experts

The correct Answer is:
C

`Fe^(2+)` ion electronic configuration is `4s^(0)3d^(6)` and has 4 unpaired electrons.so magnetic moment is
`mu=sqrt(n(n+2))`B.M`=sqrt(4(4+2))=sqrt(24)` `therefore` The magnetic moment of `Fe^(2+)` ion is approximately equal to 5.
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  • The calculated spin magnetic moment of Fe(II) is :

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  • The expected spin only magnetic moments for [Fe(CN)_6]^4- and [FeF_6]^3-] are

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