The expected spin magnetic moment of `Fe^(3+)` is :

Options

A. 4
B. 7
C. 5
D. 6

Answer

C

Explanation

`Fe^(2+)` ion electronic configuration is `4s^(0)3d^(6)` and has 4 unpaired electrons.so magnetic moment is
`mu=sqrt(n(n+2))`B.M`=sqrt(4(4+2))=sqrt(24)` `therefore` The magnetic moment of `Fe^(2+)` ion is approximately equal to 5.